The area of trapezium having its parallel sides equal to x + 3 and 2x + 7 and its height 18 cm

is 144 cm^{2}. The difference of its parallel sides is:

This question was previously asked in

MP Police Constable Previous Paper 18 (Held On: 28 Aug 2017 Shift 2)

- 7 cm
- 10 cm
- 6 cm
- 5 cm

Option 3 : 6 cm

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**Given:**

parallel sides = x + 3 and 2x + 7

height 18 cm

The area of trapezium = 144 sq. cm

**Concept used:**

The area of trapezium = (1/2) × h × (sum of parallel sides)

**Calculation:**

sum of parallel sides = x + 3 + 2x + 7 = 3x + 10

144 = (18/2) × (3x + 10)

3x + 10 = 144/9 = 16

Then, x = 2

Difference between parallel sides = 2x + 7 - (x + 3) = (4 + 7) - (2 + 3)

**∴ The difference between parallel sides is 6 cm.**

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